The handle of a water pump is 90 cm long from its Piston rod if the pivot of handle is at a distance of 15 cm from the Piston rod
Calculate: (1) mechanical advantage of the handle.
(2) least effort required at its outer and to overcome a resistance of 60 KGF.
where it the piston rod? which side of the piviot?
To calculate the mechanical advantage of the handle, we need to determine the ratio of the length of the handle to the distance from the pivot to the piston rod.
1) Mechanical Advantage:
Mechanical Advantage = Length of handle / Distance from pivot to piston rod
Given:
Length of handle = 90 cm
Distance from pivot to piston rod = 15 cm
Mechanical Advantage = 90 cm / 15 cm = 6
So, the mechanical advantage of the handle is 6.
2) Least effort required to overcome a resistance of 60 KGF:
To calculate the least effort required, we need to consider the formula for calculating work:
Work = Effort x Distance
In this case, the distance is the length of the handle, and the effort is the least effort required. We can rearrange the formula to solve for effort:
Effort = Work / Distance
Given:
Distance = 90 cm
To calculate the work, we use the formula:
Work = Force x Distance
Given:
Force = 60 KGF
Distance = 90 cm
Work = 60 KGF x 90 cm = 5400 KGF.cm
Now, we can calculate the least effort required:
Effort = Work / Distance = 5400 KGF.cm / 90 cm = 60 KGF
Therefore, the least effort required at the outer end of the handle to overcome a resistance of 60 KGF is also 60 KGF.