If you want to heat 100 kg of water at 20 ° C for your bath, calculate the amount of heat in the water. Then demonstrate that this is equivalent to 8360 kilojoules.
20° C x 100 kg = 2000000 cal
I'm unsure what to do after converting it to calories as to demonstrate the equivalent to joules
I do not know where to start.
20 Cs is about room temperature so you must be heating it to some higher temperature:
You need a temperature DIFFERENCE
heat in = Sh * mass * change in temp
in Kilocal /kilogram deg C , Sh water is 1.00 indeed
so you have
heat in = 1 *100 * (Temp - 20)
KILOCALORIES
1 kilocalorie = 1.484 kilojoules
so
multiply by 1.484 to get kilojoules
By the way if it is 8360 kilojoules that is 8360/1.484 = 5633 kilocalories
so 56.33 = T-20
so that bath water temp must have been 76.33 deg C but that is doing the problem backwards
To demonstrate the equivalence to joules, you need to convert the calories to kilojoules.
To convert calories to kilojoules, you need to use the conversion factor: 1 calorie = 4.184 kilojoules.
Let's perform the conversion:
2000000 cal x (4.184 kJ/1 cal) = 8368000 kJ
Therefore, the amount of heat in the water is equivalent to 8368000 kilojoules.