A Statement : A boy pushes a shopping trolley (weight due 2 gravity of 150N) with a constant force of 75N . A constant frictional force of 20N is present 1, Draw a laballed force diagram n a free body diagram of all the forces acting on the trolley. .....2, Determine the resultant force of all the,forces acting on the trolley
weight is down. friction is horizontal, opposite pushing force. Pushing force is horizontal.
I can't draw a force diagram here.
weight is down. friction is horizontal, opposite pushing force. Pushing force is horizontal.
I want to know why I answer this
To draw a labeled force diagram and a free body diagram of all the forces acting on the trolley, follow these steps:
1. Start by drawing a simple outline of the trolley on a sheet of paper, representing its shape and size.
2. Identify the forces acting on the trolley. In this case, there are three forces: the force due to gravity, the pushing force applied by the boy, and the frictional force.
3. Draw arrows to represent each force. Label each arrow with the name of the force and its magnitude. Here's how to represent each force:
- The force due to gravity is 150N, so draw an arrow pointing downwards with a label "Weight" or "Force due to gravity" and a magnitude of 150N.
- The pushing force applied by the boy is 75N, so draw an arrow in the direction of the push with a label "Pushing force" and a magnitude of 75N.
- The frictional force is 20N, so draw an arrow opposing the direction of motion with a label "Frictional force" and a magnitude of 20N.
4. The force diagram should now represent all the forces acting on the trolley.
To determine the resultant force of all the forces acting on the trolley, follow these steps:
1. Identify all the forces acting on the trolley, which we have already determined: the force due to gravity (150N), the pushing force (75N), and the frictional force (20N).
2. Calculate the net force by summing up all the forces acting in the same direction and subtracting any forces acting in the opposing direction. In this case, the pushing force and the frictional force are acting in opposite directions, so you subtract them. The equation would be:
Net force = Pushing force - Frictional force
Net force = 75N - 20N
Net force = 55N
Therefore, the resultant force of all the forces acting on the trolley is 55N.
Note: If the net force was zero, it would indicate that all the forces are balanced, and the trolley is either at rest or moving at a constant velocity.