A line has the equation x = my + b for some real nonzero constants m and b.
a. In terms of m and/or b, what is the x-intercept of this line?
b. In terms of m and/pr b, what is the slope of this line?
I have no idea how to solve this, so please walk me through to the answer.
Thanks in advance!
x = my + b
a. for the x-intercept isn't y = 0?
so x = b
b. change it to the y-intercept - slope form
my = x - b
y = (1/m)x - b/m
so the slope is 1/m
I understand it now.
symbolab
To find the x-intercept of the line, we need to determine the value of x when y is equal to 0.
a. To do this, let's substitute y = 0 into the equation x = my + b:
x = m(0) + b
x = b
The x-intercept, therefore, is equal to b. So, in terms of m and b, the x-intercept of this line is simply b.
b. To find the slope of the line, we can rearrange the equation x = my + b to isolate y:
x = my + b
x - b = my
y = (x - b)/m
From this equation, we can see that the coefficient of y is (1/m). Therefore, the slope of the line is 1/m.
In summary:
a. The x-intercept of the line is b.
b. The slope of the line is 1/m.