In our lab, the data consists of
1. Volume of NaOCl (mL): Trial 1= 10 ml & Trial 2= 10 mL. How can we find the concentration (Molarity), what would the calculated value be?
2. Volume of H2O2 (mL): Trial 1= 1/ml & Trial 2= 1/mL. How can we find the given value for concentration (Molarity)
What are you titrating the NaOCl with?
H2O2 same question.
bleach is what NaOCl and H2O2 is being titrated with
Here is what I did, but I'm not sure.
1. 10 g / 74.44 g NaOCl = 0.134/0.01 L = 13.4 which is the calculated value for NaOCl
2. 11 g/34.0147 = 0.323/0.011 L = 29.4 M. for the Given value of H2O2. Is this correct?
You didn't answer my question. I know you are titrating bleach and H2O2. What are you titrating it with and what is the concentration of the material with which you are titrating it.
To find the concentration (molarity) of a solution, you need to know the volume of the solution and the amount of solute present in that volume. In this case, let's assume NaOCl is the solute.
For the first question:
1. Start by calculating the moles of NaOCl using the volume provided. Since the volume is given in mL, convert to liters by dividing by 1000.
Moles of NaOCl = Volume of NaOCl (L) * Concentration of NaOCl (mol/L)
2. Next, calculate the molarity using the moles of solute and the volume of the solution.
Molarity (M) = Moles of NaOCl / Volume of the solution (L)
To find the actual calculated value for concentration (molarity), we need the concentration of NaOCl. This information is not provided in your question, so it cannot be calculated without this missing data.
For the second question, a similar process can be used:
1. Calculate the moles of H2O2 using the volume provided.
Moles of H2O2 = Volume of H2O2 (L) * Concentration of H2O2 (mol/L)
2. Find the molarity using the moles of solute and the volume of the solution.
Molarity (M) = Moles of H2O2 / Volume of the solution (L)
Similarly, without the concentration of H2O2 provided, we cannot determine the calculated value for concentration (molarity).