You toss a ball up at 7.3m/s leaving your hand at 1.5 m above the floor. What is the balls velocity just before it hits the floor.

Is the answer 2.7 m/s

Suppose a second ball is tossed straight down at 7.3 m/s (from the same place 1.5 m above the floor). What would its velocity be just before it hits the floor?

Is it stll 2.7m/s

When would the second ball eventually hit the floor?

Is the answer 1.7 seconds.

To find the velocity of the ball just before it hits the floor when tossed upwards, you can use the equation of motion:

v^2 = u^2 + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration (in this case, due to gravity -9.8 m/s^2), and s is the displacement.

Given:
u = 7.3 m/s (tossed upwards)
s = 1.5 m (displacement above the floor)

First, let's find the time it takes for the ball to reach the floor using the equation:

s = ut + (1/2)at^2

1.5 = (7.3)t + (1/2)(-9.8)t^2

Rearranging the equation, we get a quadratic equation:

-4.9t^2 + 7.3t - 1.5 = 0

By solving this quadratic equation, you will find the time it takes for the ball to reach the floor. In this case, the time is approximately 0.56 seconds.

Now, substituting the time back into the equation of motion:

v^2 = (7.3)^2 + 2(-9.8)(-1.5)

v^2 = 53.29 + 29.4

v^2 = 82.69

v = √82.69

v ≈ 9.1 m/s

Therefore, the velocity of the ball just before it hits the floor when tossed upwards is approximately 9.1 m/s.

Now let's consider the second ball tossed straight down at the same velocity (7.3 m/s) from the same height (1.5 m above the floor).

The time it takes for the second ball to hit the floor can be found using the same equation as before:

1.5 = (7.3)t + (1/2)(-9.8)t^2

By solving this equation again, the time is approximately 0.8 seconds.

Since the ball is tossed downwards, the initial velocity is negative (7.3 m/s).

Using the equation of motion:

v^2 = u^2 + 2as

v^2 = (-7.3)^2 + 2(-9.8)(1.5)

v^2 = 56.29 + 29.4

v^2 = 85.69

v = √85.69

v ≈ 9.3 m/s

Therefore, the velocity of the second ball just before it hits the floor is approximately 9.3 m/s.

As for the time it takes for the second ball to hit the floor, it is approximately 0.8 seconds, not 1.7 seconds.