A .25 kg pool ball is moving at 5.0m/s E towards a second identical ball at rest. After the collision, the first ball is seen moving at 1.0 m/s E. what is the final velocity of the second ball?
initial momentum=final momentum
.25*5+0=.25*1+.25V
solve for V
4.0 m/s E
To find the final velocity of the second ball after the collision, we can use the principle of conservation of linear momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is calculated by multiplying its mass and velocity. In this case, the momentum of the first ball before the collision is given by (mass of first ball) x (velocity of first ball before collision) = 0.25 kg x 5.0 m/s = 1.25 kg·m/s.
Since the second ball is initially at rest, its momentum before the collision is 0 kg·m/s.
After the collision, the momentum of the first ball is (mass of first ball) x (velocity of first ball after collision) = 0.25 kg x 1.0 m/s = 0.25 kg·m/s.
According to the principle of conservation of linear momentum, the total momentum before the collision (1.25 kg·m/s) should be equal to the total momentum after the collision. Therefore, the final momentum of the second ball is 1.25 kg·m/s - 0.25 kg·m/s = 1.00 kg·m/s.
To find the final velocity of the second ball, we divide its final momentum by its mass: (final momentum of second ball) ÷ (mass of second ball) = 1.00 kg·m/s ÷ 0.25 kg = 4.0 m/s.
Thus, the final velocity of the second ball after the collision is 4.0 m/s E.
M1 = 0.25kg, V1 = 5.0 m/sw.
M2 = 0.25kg, V2 = 0.
V3 = 1.0 m/s = Velocity of M1 after the
collision.
V4 = ?.
Momentum before = Momentum after
M1*V1 + M2*V2 = M1*V3 + M2^V4.
0.25*5 + 0.25*0 = 0.25*1.0 * 0.25^V4,
V4 = ?