Sally and Mercian each have some money,if sally spend$45perbday and mervin spent 15 each day,sally would have $120 left by the time mervin spent his money if sally spent$15each day,Marvin spent $45 each day,sally would have 1080 left by the time Marvin spent all his money how much do they have altogether
45x+120=15y
15x+1080=45y
check:
45*6+120=15*26
Do you see the typo in the question as posted?
Naughty, naughty!
To solve this problem, we will use a system of equations. Let's assume Sally has "S" dollars and Mervin has "M" dollars.
From the given information:
1) If Sally spends $45 per day and Mervin spends $15 per day, Sally would have $120 left by the time Mervin spent his money. This can be written as:
S - 45d = 120 Eq(1)
2) If Sally spends $15 per day and Mervin spends $45 per day, Sally would have $1080 left by the time Mervin spent all his money. This can be written as:
S - 15d = 1080 Eq(2)
To find the values of S and M, we'll solve this system of equations.
First, let's solve Eq(1) for S in terms of d:
S = 45d + 120
Now, substitute this value of S into Eq(2):
45d + 120 - 15d = 1080
Combine like terms:
30d + 120 = 1080
Simplify:
30d = 960
Divide both sides by 30:
d = 32
Now, substitute d = 32 into either Eq(1) or Eq(2) to find the values of S and M. Let's use Eq(1):
S = 45(32) + 120
S = 1440
So, Sally has $1440 and since Mervin has the remaining money, he has:
M = S - 45d
M = 1440 - 45(32)
M = 1440 - 1440
M = 0
Therefore, Sally has $1440 and Mervin has $0.
To find the total amount of money they have altogether:
Total = Sally's money + Mervin's money
Total = $1440 + $0
Total = $1440
So, Sally and Mervin have a total of $1440 altogether.