An airplane from rest accelerates on a runway at 5.50 m/s² for 20:25 seconds until it finally takes off the ground. What is the acceleration before the take off?
Umm, I'd guess 5.50 m/s^2, eh?
Maybe you want take-off speed?
v = at
To find the acceleration before takeoff, we need to use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity is zero because the airplane is at rest. The final velocity is the velocity at takeoff, which we don't know yet. However, we do know the time it takes for the acceleration to occur, which is 20 minutes and 25 seconds.
First, we need to convert 20 minutes and 25 seconds into seconds. There are 60 seconds in a minute, so:
20 minutes = 20 x 60 = 1200 seconds
25 seconds = 25 seconds
Therefore, the total time is 1200 + 25 = 1225 seconds.
Now, we can plug the values into the formula:
acceleration = (final velocity - initial velocity) / time
5.50 = (final velocity - 0) / 1225
Next, we can solve for the final velocity. Multiply both sides of the equation by 1225:
(5.50)(1225) = final velocity - 0
6743.75 = final velocity
Therefore, the final velocity at takeoff is approximately 6743.75 m/s.