Calculate the linear expansivity of a brass of length 120m that assume a new length of 120.05m when heated through a temperature of 100°c

linear expansivity =L2-L1/L1<tita>

linear expansivity=120.05-120 / 120<100>
linear expansivity=0.05 / 12,000
linear expansivity=0.000417

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Expansivity is expressed in m/° = ∆L/∆T, so what do you think?

Help me calculate the linear expansivity of a brass of length 120m that assumes a new length of 12.05m when heated through a temperature.

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