suppose the hydrate was heated too quickly and some of it was lost as it spattered out of the container . explain how this would effect .
a. the calculated mass of water in the compound
b. the molecular formula you determined.
than you Drbob222 ,, what i heated was the hydrate , but ur answer still makes since ,, thank you very much
thank you Drbob222 ,, what i heated was the hydrate , so all i had to do was heat about 3 grams of hydrate till all of the water is evaporated < its turns into a pale color> so when the water is gone it becomes anhydrous copper 2 sulfate , so i really hope that helps you understand what i meant by my questions ,, and thank you again .
a. The loss of hydrate due to spattering would affect the calculated mass of water in the compound. To understand why, we need to know how the mass of water is determined in the first place. In a typical experiment, the hydrate is heated to remove the water, and the difference in mass before and after heating gives the mass of water. However, if some of the hydrate spatters out during the rapid heating, it means that we would be left with less sample to measure afterwards. As a result, the calculated mass of water would be underestimated because the lost hydrate is not accounted for in the measurement.
b. The loss of hydrate would also affect the molecular formula you determined. The molecular formula is determined based on the ratio between the moles of water and moles of the anhydrous compound. If some of the hydrate is lost during spattering, the ratio between the moles of water and the moles of the anhydrous compound will be altered. This means that the ratio you calculate would deviate from the actual stoichiometric ratio in the compound, resulting in an incorrect molecular formula determination.
In summary, the loss of hydrate due to spattering during rapid heating affects both the calculated mass of water and the molecular formula you determine. The mass of water would be underestimated, and the altered ratio of moles between water and the anhydrous compound would lead to an incorrect molecular formula.
Have you considered helping a little by telling us what you heated and the details of the experiment?
a. All things being equal, losing part of the material due to spattering would make the second weighing lower than it should be. That makes the measured mass of water too high.
b. Since I don't know what experiment you are doing, I will leave this for you and you can use the answer from part a to determine part b.