Write 2 complete Bronsted/Lowry acid/base reactions for the reaction between HC2c2O4- and HPO42-. Identify all conjugate pairs.

my answers:
HC2O4- + HPO42- -> H2C2O4 + PO43-

HC2O4- and H2C2O4 are conjugate pairs

HPO42- and PO43- are conjugate pairs

HC2O4- + HPO42- -> C2O42- + H2PO4-

HC2O4- and C2O42-

HPO42- and H2PO4-

correct

@bobpursley i feel like i did the signs wrong?

Your answers are correct:

1. HC2O4- + HPO42- -> H2C2O4 + PO43-
Conjugate pairs: HC2O4- (acid) and H2C2O4 (conjugate base)
HPO42- (base) and PO43- (conjugate acid)

2. HC2O4- + HPO42- -> C2O42- + H2PO4-
Conjugate pairs: HC2O4- (acid) and C2O42- (conjugate base)
HPO42- (base) and H2PO4- (conjugate acid)

To write Bronsted/Lowry acid/base reactions and identify conjugate pairs, we need to understand the concept of acids and bases. In the Bronsted/Lowry acid/base theory, an acid is a substance that donates a proton (H+), while a base is a substance that accepts a proton.

In this case, we have HC2O4- (hydrogen oxalate ion) and HPO42- (hydrogen phosphate ion). To determine the acid and base in each reaction, we need to identify which species donates a proton and which species accepts a proton.

Reaction 1:
HC2O4- + HPO42- -> H2C2O4 + PO43-

In this reaction, HC2O4- donates a proton (H+) to HPO42-, making HC2O4- the acid and HPO42- the base.

Conjugate acid/base pairs:
- HC2O4- (acid) and H2C2O4 (conjugate base)
- HPO42- (base) and PO43- (conjugate acid)

Reaction 2:
HC2O4- + HPO42- -> C2O42- + H2PO4-

In this reaction, HC2O4- donates a proton (H+) to HPO42-, making HC2O4- the acid and HPO42- the base.

Conjugate acid/base pairs:
- HC2O4- (acid) and C2O42- (conjugate base)
- HPO42- (base) and H2PO4- (conjugate acid)

So, to summarize:
Reaction 1:
Acid: HC2O4-, Base: HPO42-
Conjugate acid/base pairs: HC2O4- / H2C2O4, HPO42- / PO43-

Reaction 2:
Acid: HC2O4-, Base: HPO42-
Conjugate acid/base pairs: HC2O4- / C2O42-, HPO42- / H2PO4-