A water pump of 1.2kilowatts rating,pumps 480g of water into an over head tank at a height of 5m in 30 seconds. What is d efficiency of d time
m = 0.48 kg are you sure you mean grams?
You do not usually use a pump that powerful for so little mass. (about a horsepower to move one pound up 15 feet in 30 seconds.)
power in = 1200 Watts
energy in = 1200 *30 Joules
work out = 0.48 * 9.81 * 5 Joules
so eff = work out/energy in
= 0.48*9.81*5/(1200*30)
= 6.54 * 10^-4
I think you may mean 480 kg
Mass = 480kg?
F = M*g = 480 * 9.8 = 4704 N.
Po = F*d/t = 4704 * 5/30 = 784 J./s = 784 Watts. = Power out.
Eff. = Po/Pi = 784/1200 = 0.653 = 65.3%.
To calculate the efficiency of the water pump, you need to determine the work done by the pump and divide it by the input energy (power) provided to the pump.
First, let's calculate the work done by the pump. The work done, W, can be calculated using the formula:
W = Force × Distance
In this case, the force is the weight of the water pumped, and the distance is the height the water is pumped. The weight, which is the force due to gravity, can be calculated using the formula:
Weight = Mass × Gravity
Since we know the mass of water pumped, we can calculate the weight, where
Mass = 480g = 0.48kg (converting grams to kilograms)
Gravity = 9.8 m/s² (acceleration due to gravity)
Weight = 0.48 kg × 9.8 m/s²
Now, let's calculate the work done by the pump
W = Weight × Distance
W = (0.48 kg × 9.8 m/s²) × 5 m
Next, calculate the input energy (power) provided to the pump. The power, P, is given as 1.2 kilowatts.
P = 1.2 kilowatts = 1200 watts
The input energy (E) can be calculated by multiplying the power by time:
E = Power × Time
E = 1200 watts × 30 seconds
Now, we can calculate the efficiency (η) using the formula:
η = (Work/Output Energy) * 100
η = (W / E) * 100
Substituting the previously calculated values:
η = ((0.48 kg × 9.8 m/s²) × 5 m) / (1200 watts × 30 seconds) * 100
Therefore, the calculated efficiency will be the percentage of the input energy that is converted to useful work.