I'd like to know if I'm understanding how to set up the problem.

Mrs. Vasquez selects a marble from a jar containing 6 red marbles and 2 green marbles, and does not replace it. She then selects a second marble and does not replace it. She then selects a third marble. What is the probability that all three marbles will be red?

I have my problem set up as: 1/8 * 6/6=

Is this correct? Thank you.

Not quite

1st draw: 6 red of 8
2nd draw: 5 red of 7
...
so, the probability of all 3 reds is

6/8 * 5/7 * 4/6

I'll get it one day. Appreciate the help.

To set up the problem correctly, let's break it down step by step:

Step 1: Determine the probability of selecting a red marble on the first draw.
Out of a total of 8 marbles (6 red and 2 green), the probability of selecting a red marble on the first draw is 6/8, since there are 6 red marbles out of a total of 8 marbles.

Step 2: Determine the probability of selecting a red marble on the second draw without replacement.
After the first red marble is chosen and not replaced, there are now only 7 marbles left in the jar, with 5 red marbles and 2 green marbles. The probability of selecting a red marble on the second draw is 5/7, since there are 5 red marbles out of a total of 7 remaining marbles.

Step 3: Determine the probability of selecting a red marble on the third draw without replacement.
After the second red marble is chosen and not replaced, there are now only 6 marbles left in the jar, with 4 red marbles and 2 green marbles. The probability of selecting a red marble on the third draw is 4/6, since there are 4 red marbles out of a total of 6 remaining marbles.

Finally, to find the probability of all three marbles being red, we multiply the probabilities from each step together:

P(all three marbles are red) = (6/8) * (5/7) * (4/6)

Now let's simplify:

P(all three marbles are red) = (3/4) * (5/7) * (2/3) = 30/84 = 5/14

So the correct probability of all three marbles being red is 5/14, not 1/8.