what are the workings of this question? A brass rod is 2m long at a certain temperature.what is the length for a temperature rise of 100k, if the expansivity of brass is 18x10-6k-1

newlength=oldlength(1+18e-6)(changinTemp)

I dont no

To understand the workings of this question, we will need to use the concept of thermal expansion and the given expansivity of brass.

Thermal expansion refers to the tendency of a material to change in shape, volume, or length in response to a change in temperature. Different materials have different coefficients of thermal expansion, which quantifies how much the material will expand or contract for a given change in temperature.

In this question, we are given that a brass rod is initially 2m long at a certain temperature. We need to find the length of the rod for a temperature rise of 100K, given that the expansivity (coefficient of thermal expansion) of brass is 18x10^(-6)K^(-1).

To calculate the change in length of the brass rod, we can use the formula:

ΔL = α * L * ΔT

Where:
ΔL is the change in length
α is the coefficient of thermal expansion
L is the initial length of the rod
ΔT is the change in temperature

Substituting the given values in the formula, we have:

ΔL = (18x10^(-6)K^(-1)) * (2m) * (100K)

ΔL = (18 * 10^(-6)) * (2) * (100)

ΔL = 0.036m

Therefore, the length of the brass rod for a temperature rise of 100K is 0.036m longer than its initial length of 2m.