Can someone help me solve this problem? This example problem will help me solve the actual homework problems
If an 0.6kg apple is dropped from 0.5m height onto a seesaw and flips up a 0.25kg kiwi. To what height does that kiwi reach. Assume all the energy of the apple transfers perfectly to the kiwi
PE = mgh is conserved. So since the apple's mass is .6/.25 = 2.4 times the kiwi's, the kiwi rises to 2.4 times the apple's height.
the apple's energy is ... m g h
Ma * g * Ha = Mk * g * Hk
Ma / Mk = Hk / Ha
the height is inversely proportional to the mass ... heavier things don't go as high
Of course, I can help you solve this problem!
To find the height that the kiwi reaches, we can use the conservation of energy principle. According to this principle, the potential energy lost by the apple is equal to the potential energy gained by the kiwi.
The potential energy of an object can be calculated using the formula:
PE = m * g * h
Where:
PE is the potential energy,
m is the mass of the object,
g is the acceleration due to gravity (approximately 9.8 m/s²),
h is the height.
Let's calculate the potential energy lost by the apple:
PE_apple = m_apple * g * h_apple
Given:
m_apple = 0.6 kg
h_apple = 0.5 m
PE_apple = 0.6 kg * 9.8 m/s² * 0.5 m
Now, since the energy is perfectly transferred to the kiwi, the potential energy gained by the kiwi will be equal to the potential energy lost by the apple:
PE_kiwi = PE_apple
We can rearrange the formula to solve for the height reached by the kiwi:
h_kiwi = (PE_kiwi) / (m_kiwi * g)
Given:
m_kiwi = 0.25 kg
h_kiwi = (PE_apple) / (0.25 kg * 9.8 m/s²)
Now, you can plug in the values and calculate the final result.