Mr. Challenger randomly selected two apples without replacing the first apple from a crate containing 10 green apples, 14 red apples, and 18 yellow apples. What is the probability that he selected a yellow apple first and a green apple second?
prob(yellow, then green)
= (18/42)(10/41)
= ....
Thank you so much.
To find the probability, we first need to determine the total number of possible outcomes and the number of favorable outcomes.
Total number of possible outcomes:
Mr. Challenger could choose any of the 42 apples in the crate as the first pick, and then any of the remaining 41 apples as the second pick. So, the total number of possible outcomes is 42 * 41 = 1,722.
Number of favorable outcomes:
Mr. Challenger can select a yellow apple first from the 18 yellow apples, and then a green apple from the 10 green apples. So, the number of favorable outcomes is 18 * 10 = 180.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
= 180 / 1,722
≈ 0.1047
Therefore, the probability that Mr. Challenger selected a yellow apple first and a green apple second is approximately 0.1047 or 10.47%.