algebra

in a 3 digit number, the tens digit is twice the hundreds digit and 1/2 the units digit. if the digits are reversed, the new number is 49 more than 3 times that of the original number

asked by John
  1. t = 2h ... 2t = u ... 4h = u

    3*(100h + 10t + u) + 49 = 100u + 10t + h

    3*(100h + 20h + 4h) + 49 = 400h + 20h + h

    solve for h , then find t and u

    posted by Scott

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