# calculus

If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by
y = 52t − 1.86t2.

What is the average speed over the given time intervals?

(i) [1, 2]

(ii) [1, 1.5]

(iii) [1, 1.1]

(iv) [1, 1.01]

(v) [1, 1.001]

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1. I will do one of them, you do the rest
(iii) [1, 1.1]
when x=1, y = 52-1.86 = 50.14
when x = 1.1, y = 52(1.1)-1.86(1.1)^2 = 54.72434

avg speed= (54.72434-50.14)/(1.1-1)
= 45.8434 m/s

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