the maximum solubility of nacl in water to form brine at 0 c is 26% (mass/volume.) the density of the solution is 1.2 g/ml
To determine how much NaCl can be dissolved in water to form a 26% brine solution at 0°C, we'll need to consider the solubility limit and the density of the solution. Let's break it down step by step:
Step 1: Calculate the mass of 1 ml of the 26% brine solution.
Since the density of the solution is given as 1.2 g/ml, it means that 1 ml of the solution has a mass of 1.2 grams.
Step 2: Determine the maximum mass of NaCl that can be dissolved in 1 ml of water at 0°C to form a 26% solution.
If the solution is 26% NaCl by mass, it means that 1 ml of the solution contains 26% of NaCl's maximum solubility. To find the maximum mass that can be dissolved, we can set up the following equation:
Mass of NaCl / Total mass of the solution = 26/100
Let's assume the maximum mass of NaCl that can be dissolved in 1 ml of water is "X" grams. The total mass of the solution would then be "X + 1.2" grams. Using the equation above, we can solve for X:
X / (X + 1.2) = 26/100
Simplifying the equation, we get:
100X = 26(X + 1.2)
100X = 26X + 31.2
100X - 26X = 31.2
74X = 31.2
X ≈ 0.421 g
Therefore, approximately 0.421 grams of NaCl can be dissolved in 1 ml of water at 0°C to form a 26% brine solution.
Step 3: Calculate the maximum solubility of NaCl in water to form a 26% brine solution.
To find the maximum solubility, we need to convert the mass of NaCl to a percentage by mass/volume.
Maximum solubility = (Mass of NaCl / Volume of water) × 100
Since we know that the mass of NaCl is approximately 0.421 grams and we are considering 1 ml of water, we can calculate:
Maximum solubility = (0.421 g / 1 ml) × 100
Maximum solubility ≈ 42.1%
Therefore, the maximum solubility of NaCl in water to form a 26% brine solution at 0°C is approximately 42.1% (mass/volume).