A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.993 s. How much time passes during his entire trip from the top down to the water? Ignore air resistance.
Pls help and explain!
To solve this problem, we can use the equations of motion for an object in free fall. The first step is to determine the time it takes for the object to fall halfway down to the water.
We are given that the time taken to fall halfway down is 0.993 s. Since the object is falling vertically, the time taken to fall halfway is also equal to half the total time taken for the entire trip.
Let's call the total time for the trip "t". Therefore, we have:
0.993 s = t/2
To solve for "t", we can multiply both sides of the equation by 2:
2 * 0.993 s = t
1.986 s = t
So, the total time taken for the entire trip from the top down to the water is 1.986 seconds.
h = 1/2 g t^2 ... t = √(2 h / g)
if h is doubled , t is multiplied by √2