Calculate the [MnO4-] concentration of the diluted sample when the sample is prepared in the following manner. Add 2 drops oxalic acid, 4 drops permanganate and 8 drops water. The original permanganate is 0.25M. Help!

https://www.jiskha.com/display.cgi?id=1485377030

To calculate the [MnO4-] concentration of the diluted sample, we need to use the concept of dilution. Dilution is a process in which the concentration of a solution is decreased by adding more solvent.

Let's start by understanding what is given:

Original permanganate concentration: 0.25 M
Number of drops of permanganate added: 4 drops
Number of drops of water added: 8 drops

To calculate the concentration of the diluted sample, we need to calculate the final volume of the solution after dilution. Each drop of liquid doesn't have a standard volume, so we'll assume that 1 drop is approximately 0.05 mL.

The total volume of the original solution can be calculated as follows:
Total volume = (number of drops of permanganate + number of drops of water) * volume per drop
= (4 drops + 8 drops) * 0.05 mL/drop
= 12 drops * 0.05 mL/drop
= 0.6 mL

Next, we'll calculate the moles of permanganate added to the solution using the original permanganate concentration:

Moles of permanganate = original permanganate concentration * volume of permanganate added
= 0.25 M * 0.6 mL
= 0.15 mmol (millimoles)

Now, we'll calculate the final volume of the diluted solution after adding the oxalic acid and water. Since the drops of oxalic acid and water don't have given volumes, we'll assume that 2 drops of oxalic acid and 8 drops of water make up a total volume of 1 mL.

Total volume of diluted solution = 1 mL

Finally, we can calculate the [MnO4-] concentration of the diluted solution using the moles of permanganate and the dilution formula:

[MnO4-] = Moles of permanganate / Total volume of diluted solution
= 0.15 mmol / 1 mL
= 0.15 M

Therefore, the concentration of [MnO4-] in the diluted sample is 0.15 M.