(y+2)^2=-(x+1)
I want to know if (x+1)=-(y+2)^2 is the same thing, and if it is, then is the stretch factor -1?
It is the same. This is the identity theorem.
I don't see a stretch factor here.
I am supposed to descibe the relation, would i just say a horiz. trans. 1 left and 2 units down?
To determine if the equation (x + 1) = -(y + 2)^2 is the same as (y + 2)^2 = -(x + 1), we can compare the two equations.
The first equation, (y + 2)^2 = -(x + 1), is in the form of a quadratic equation, where y is the variable. It represents a parabola that opens vertically. The vertex of the parabola is at (-1, -2), and it has a stretch factor of -1.
The second equation, (x + 1) = -(y + 2)^2, is also a quadratic equation, but it is in the form where x is the variable. This equation represents a parabola that opens horizontally. The vertex of the parabola is at (-1, -2), which is the same as the first equation. However, the stretch factor in this case is not -1.
Therefore, although the two equations have the same vertex, they represent different parabolas due to the difference in the variable and the opening direction.