How many mol of NaHCO3 are in a 454 g box of baking soda (NaHCO3)?

A. 3.81 x 10^4 mol NaHCO3
B. 1.85 x 10^–1 mol NaHCO3
C. 5.40 x 10^0 mol NaHCO3
D. 6.33 x 10^–20 mol NaHCO3

I tried doing the calculations and a came the closest but it wasn't exact...

2 years later and he still hasn't posted it... this is a man who sticks to his word -_-

Na = 23 g/mol

H = 1
C=12
O3 = 3*16 = 48
sum = 84 grams / mol

454 g * 1 mol/84 grams = 5.40
by the way luckily 10^0 = 1 :)

smh

Manz still hasn't posted it

still waiting on question 2

Bro really thinks we have sundials -_-

Its going to be 2023

5 years later and still waiting for that question m8

To determine the number of moles of NaHCO3 in a 454g box of baking soda, you need to use the molar mass of NaHCO3.

The molar mass of NaHCO3 is calculated by adding up the atomic masses of its constituent elements: sodium (Na), hydrogen (H), carbon (C), and oxygen (O).

The atomic masses for these elements are as follows:
- Na: 22.99 g/mol
- H: 1.01 g/mol
- C: 12.01 g/mol
- O: 16.00 g/mol

To find the molar mass of NaHCO3, you multiply the atomic mass of each element by the number of atoms present in the formula, then sum them up:
(1 x Na) + (1 x H) + (1 x C) + (3 x O) = 22.99 + 1.01 + 12.01 + 3(16.00) = 84.01 g/mol

Now, you can use the molar mass to calculate the number of moles of NaHCO3:

Number of moles = Mass of substance (g) / Molar mass (g/mol)

Plugging in the values, we have:
Number of moles = 454 g / 84.01 g/mol

Using a calculator, the result is approximately 5.407 mol.

Therefore, the choice that corresponds to the correct number of moles is C. 5.40 x 10^0 mol NaHCO3.

Thanks Damon! I need help with one more question, I'm about to post it !!