# Chemistry (mol)

How many mol of NaHCO3 are in a 454 g box of baking soda (NaHCO3)?

A. 3.81 x 10^4 mol NaHCO3
B. 1.85 x 10^–1 mol NaHCO3
C. 5.40 x 10^0 mol NaHCO3
D. 6.33 x 10^–20 mol NaHCO3

I tried doing the calculations and a came the closest but it wasn't exact...

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1. Na = 23 g/mol
H = 1
C=12
O3 = 3*16 = 48
sum = 84 grams / mol

454 g * 1 mol/84 grams = 5.40
by the way luckily 10^0 = 1 :)

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posted by Damon
2. Thanks Damon! I need help with one more question, I'm about to post it !!

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posted by Michael

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