3O2 -> 2O3
When 4.26 x 10^16 mol of oxygen (O) are converted into ozone, how many mol of the pollutant (O3) are formed?
A. 2.84 x 10^16 mol O2
B. 6.39 x 10^6 mol O2
C. 2.84 x 10^1 mol O2
D. 2.84 x 10^16 mol O2
D?
oxygen (O). O does not exist, oxygen is diatomic, O2
So assuming it meant 4.26 x 10^16 mol of oxygen (O2) are converted into ozone, how many mol of the pollutant (O3) are formed?
answer: 3/2 * 4.26e16=, no answer. If B was meant to be 6.39 x 10^16, that is correct. What is going on with your problems?
i have no idea but thank you so much
you know, of course, that is quite a lot of oxygen.
To determine the number of moles of the pollutant O3 formed when 4.26 x 10^16 mol of oxygen (O) is converted, we need to consider the balanced chemical equation:
3O2 → 2O3
The coefficients in the equation tell us the stoichiometry of the reaction, which means that in order to convert 3 moles of O2, we produce 2 moles of O3.
Using this information, we can set up a proportion to find the number of moles of O3:
(2 moles O3 / 3 moles O2) = (x moles O3 / 4.26 x 10^16 moles O2)
Simplifying the proportion:
2 / 3 = x / (4.26 x 10^16)
Cross-multiplying, we have:
2 × (4.26 x 10^16) = 3x
8.52 x 10^16 = 3x
x = 8.52 x 10^16 / 3
x ≈ 2.84 x 10^16
Therefore, approximately 2.84 x 10^16 moles of the pollutant O3 are formed.
The correct answer is D. 2.84 x 10^16 mol O2.