Calculate the heat absorbed by 125 g of water (SH = 1.00 cal/g°C) when the temperature rises from 21.0°C to 35.0°C.
35-21 = 14 degrees C temp change
1 calorie/gram deg C *125 grams* 14 deg C
= 1750 calories
To calculate the heat absorbed by 125 g of water when the temperature rises from 21.0°C to 35.0°C, we can use the formula:
Q = m * c * ΔT
where:
Q is the heat absorbed
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in cal/g°C)
ΔT is the change in temperature (in °C)
Given:
m = 125 g
c (specific heat capacity of water) = 1.00 cal/g°C
ΔT = 35.0°C - 21.0°C = 14.0°C
Let's substitute these values into the formula to calculate the heat absorbed:
Q = 125 g * 1.00 cal/g°C * 14.0°C
Q = 1750 cal
Therefore, the heat absorbed by 125 g of water when the temperature rises from 21.0°C to 35.0°C is 1750 calories.