if jeff is one year older than erica, and erica is one year older than john, and their combined age is 75, how old are they now
Jeff=26 Erica=25 John=24
To find out how old Jeff, Erica, and John are now, we can set up a system of equations based on the given information.
Let's assign variables to their ages:
Let J represent John's age
Let E represent Erica's age
Let J + 1 represent Erica being one year older than John
Let J + 1 + 1 represent Jeff being one year older than Erica
Based on the given information, we can set up three equations:
1) J + (J + 1) + (J + 1 + 1) = 75 -- This equation represents their combined age being 75
2) J + 1 = E -- This equation represents Erica being one year older than John
3) E + 1 + 1 = J + 1 + 1 + 1 -- This equation represents Jeff being one year older than Erica
Simplifying the equations, we have:
1) 3J + 4 = 75
2) J + 1 = E
3) E + 2 = J + 2
Now, let's solve these equations to find their ages.
From equations 2 and 3, we can conclude that E = J + 1 and E = J + 2.
Combining these two equations, we have J + 1 = J + 2.
By subtracting J from both sides, we get 1 = 2, which is not possible.
This means there is no consistent solution to the given information. There might be a mistake in the information provided or the problem is inherently flawed.