Carla bought a digital camera that cost $91.98. She also bought 2 identical memory cards and a camera case. The camera cost 6 times as much as the case. She paid $127.35, including sales tax of $6.06. What was the cost of each memory card?
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Let's break down the problem step by step to find the cost of each memory card.
First, we need to determine the cost of the camera case. The problem states that the camera cost 6 times as much as the case. So, let's divide the total cost of the camera by 6 to find the cost of the case.
Camera case cost = $91.98 / 6 = $15.33
Next, we need to find the individual cost of the memory cards. We know that Carla bought 2 identical memory cards, so we can divide the remaining total cost by 2 to find the cost of each memory card.
Remaining total cost = Total cost - Camera cost - Case cost = $127.35 - $91.98 - $15.33 = $20.04
Cost of each memory card = Remaining total cost / 2 = $20.04 / 2 = $10.02
Therefore, each memory card costs $10.02.
127.35 - 6.06 = 121.29 total cost
camera with case = 91.98 + 91.98/6
= 107.31
so
2 m + 107.31 = 121.29