Given that it has highest electronegativy can a flourine atom ever form a nonpolar covalent bonnd?
Yes in F2 in which the eletronegativity difference between the two fluorine atoms is 0.
Fluorine (F) is indeed one of the most electronegative elements on the periodic table. Electronegativity is a measure of an atom's tendency to attract electrons towards itself when it forms a chemical bond. In general, when two atoms with a significant difference in electronegativity bond together, the bond will be polar.
A polar covalent bond is formed when there is an unequal sharing of electrons between the two atoms. In such a bond, one atom will have a slightly negative charge (due to it pulling the electrons closer to itself) and the other atom will have a slightly positive charge.
Since fluorine is the most electronegative element, it will almost always form polar covalent bonds when it bonds with less electronegative atoms. This is because fluorine strongly attracts the shared electrons towards itself, creating a partial negative charge on the fluorine atom.
However, it is possible for a fluoride ion (F-) to form a nonpolar covalent bond with another fluoride ion. This occurs when the bonding electrons are shared equally between the two identical fluorine atoms. As a result, there is no charge separation, and the bond is considered nonpolar.
In summary, while a fluorine atom itself will normally form polar covalent bonds, a fluoride ion can form a nonpolar covalent bond when it bonds with another fluoride ion.