If an electric discharge produces 300 liters of ozone (O3), how many liters of oxygen (O2) are required?
3O2->2O3
Would it require 450 L of Oxygen?
300 x 3/2 = 450
To determine how many liters of oxygen (O2) are required to produce 300 liters of ozone (O3), we need to use the given balanced chemical equation, which shows that 3 molecules of oxygen react to form 2 molecules of ozone:
3O2 -> 2O3
Now we can set up a proportion to solve the problem:
(300 L O3) / (2 O3) = (x L O2) / (3 O2)
Cross multiplying gives us:
2(x L O2) = 3(300 L O3)
2x = 3 * 300
2x = 900
Dividing both sides by 2, we find:
x = 900 / 2
x = 450
Therefore, 450 liters of oxygen (O2) are required to produce 300 liters of ozone (O3).
3O2->2O3
With gases you can use a shortcut and use volumes directly as if volumes were mols. In this case, then, just convert using the coefficients in the balanced equation.
300 L O3 x (3 mols O2/2 mols O3) = 300 x 3/2 = ?