1. Two molecules of ____ are produced by glycolysis. Each molecule has ____ carbons. C
A. Oxaloacetate...4
B. Citrate...3
C. Pyruvate...3
D. Acetate...4
2. Oxaloacetate combines with acetyl coA at the beginning of. D
A. Electron transport chain
B. Glycolysis
C. Transcription
D. Krebs cycle
3. Which nitrogenous base is not present in ribonucleic acid? D
A. Fuanine
B. Uracil
C. Cytosine
D. Thymine
correct
1. The answer is C. Pyruvate...3. Two molecules of pyruvate are produced by glycolysis, and each molecule has 3 carbons.
2. The answer is D. Krebs cycle. Oxaloacetate combines with acetyl coA at the beginning of the Krebs cycle.
3. The answer is D. Thymine. Thymine is not present in ribonucleic acid (RNA), instead it is found in deoxyribonucleic acid (DNA). RNA contains the nitrogenous bases adenine (A), guanine (G), cytosine (C), and uracil (U).
1. To answer this question, we need to understand the process of glycolysis. Glycolysis is the first step in cellular respiration where glucose is broken down into two molecules of pyruvate. Therefore, the correct answer is C. Pyruvate, which is a three-carbon molecule, is produced by glycolysis.
2. This question is asking about the molecule that combines with oxaloacetate at the beginning of a specific process. To determine the correct answer, we need to identify the process in which oxaloacetate participates. The only process listed that involves oxaloacetate is the Krebs cycle (also known as the citric acid cycle). Therefore, the correct answer is D. Krebs cycle.
3. Ribonucleic acid (RNA) is a molecule that plays a crucial role in protein synthesis. It consists of nucleotides, which are made up of a sugar (ribose), a phosphate group, and a nitrogenous base. The four nitrogenous bases found in RNA are adenine (A), uracil (U), cytosine (C), and guanine (G). Thymine (T) is a nitrogenous base that is exclusively found in deoxyribonucleic acid (DNA). Hence, the correct answer is D. Thymine.