The speed of the tip of a second hand of length 5 cm of a clock is m/s
5.3*10-³
To calculate the speed of the tip of a second hand, we need to know two things: the length of the second hand and the angular speed of the hand.
Given:
Length of the second hand = 5 cm
The angular speed of the second hand can be calculated using the formula:
Angular speed = (2π * Number of revolutions) / Time taken
In the case of a clock, the second hand completes one full revolution (360 degrees) every 60 seconds. Therefore, the number of revolutions of the second hand in one second is 1/60.
Now, let's calculate the angular speed:
Angular speed = (2π * (1/60)) / 1
= π/30 rad/s
To find the linear speed of the tip of the second hand, we can use the formula:
Linear speed = Angular speed * Radius
Since the length of the second hand is given in centimeters, we need to convert it to meters before using it as the radius:
Radius = 5 cm = 0.05 m
Now, we can calculate the linear speed:
Linear speed = (π/30) * 0.05
≈ 0.00524 m/s
Therefore, the speed of the tip of a second hand of length 5 cm of a clock is approximately 0.00524 m/s.
0.0052
The second hand travels 1/60 of the circumference of a circle made by its tip in a second.
Circumference of the clock = 2*pi*r
= 2 * pi * 5
= 10*pi cm
Distance traveled in a second = C/60
= (10*pi)/60
= pi/6
= 0.52 cm/sec
= 0.0052m/sec