How much energy is given out whwn 1g of methane burns
Do you know delta Ho for CH4? It should be in tables in your text.
To calculate the amount of energy given out when 1 gram of methane (CH4) burns, we need to use the concept of molar mass and the heat of combustion of methane.
Step 1: Determine the molar mass of methane (CH4):
Carbon (C) has a molar mass of approximately 12 grams per mole.
Hydrogen (H) has a molar mass of approximately 1 gram per mole.
We have 1 carbon atom and 4 hydrogen atoms in methane, so the molar mass of methane is:
(1 * 12 g/mol) + (4 * 1 g/mol) = 16 g/mol.
Step 2: Calculate the heat of combustion of methane:
The heat of combustion of methane is the energy released when one mole of methane undergoes complete combustion. It is approximately 890 kJ/mol.
Step 3: Convert grams of methane to moles:
Since we have 1 gram of methane, we divide it by the molar mass of methane to convert grams to moles:
1 g / 16 g/mol ≈ 0.0625 moles.
Step 4: Calculate the energy released:
Multiply the moles of methane by the heat of combustion to determine the energy released:
0.0625 moles * 890 kJ/mol = 55.625 kJ.
Therefore, when 1 gram of methane burns, it gives out approximately 55.625 kilojoules (kJ) of energy.