One cant solve this without knowing the time involved, or the mass of steam.
steamers are vessels you can use to cook food in.food in steamer gains heat as the steam condenses on it.a boiler supplies steam at 105 degree to a steamer at the tare of 445 g min-1
what is the amount of heat 445 g of steam would release by cooling from 105 dree to 100 dree without changing state?
To find the amount of heat released by 445 g of steam cooling from 105°C to 100°C without changing state, you need to use the specific heat capacity formula. It is given as:
Q = m * c * ΔT
Where:
Q = Amount of heat energy (in joules)
m = Mass of the substance (in grams)
c = Specific heat capacity of the substance (in J/g°C)
ΔT = Change in temperature (in °C)
In this case, the mass of steam is given as 445 g, and the change in temperature is from 105°C to 100°C. However, the specific heat capacity is not provided.
To solve this problem, you need to find the specific heat capacity of steam. The specific heat capacity for water is approximately 4.18 J/g°C, so we can assume it to be the same for steam as well. However, this value may vary slightly depending on the pressure.
Once we have the specific heat capacity value (c), we can substitute the values into the formula to find the amount of heat released (Q).
So, to answer the question accurately, we need to know the specific heat capacity of steam.