A volleyball is served at the speed of 8.0 m/s at an angle 35° above the horizontal. What is the speed of the ball when received by the opponent at the same height

Parabola is symmetric so the same.

answer please

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To find the speed of the ball when received by the opponent at the same height, we need to consider the horizontal and vertical components of the ball's initial velocity.

First, let's find the horizontal component of the ball's initial velocity (Vx). We can use the formula:

Vx = V * cos(θ)

Where:
V is the magnitude of the initial velocity (8.0 m/s)
θ is the angle of the initial velocity (35°)

So, Vx = 8.0 * cos(35°) ≈ 6.57 m/s

Next, let's find the vertical component of the ball's initial velocity (Vy). We can use the formula:

Vy = V * sin(θ)

Vy = 8.0 * sin(35°) ≈ 4.57 m/s

Since the ball is received at the same height, the vertical component of the final velocity will be the same as the initial velocity (Vy = 4.57 m/s).

To find the speed of the ball when received by the opponent, we need to combine the horizontal and vertical components of the final velocity using the Pythagorean theorem:

Vfinal = sqrt((Vx)^2 + (Vy)^2)

Vfinal = sqrt((6.57)^2 + (4.57)^2) ≈ 7.92 m/s