a) What is the probability of obtaining 2 Heads when a coin is tossed twice?

b) What is the probability of obtaining 1 Head when a coin is tossed twice?

Keep in mind, the coins are not tossed simultaneously.

Taking H = getting heads, and T = getting tails,

The sample space of the event of tossing a coin twice is as follows:

S = {(H,H),(T,H),(H,T),(H,H)}

There are a total of four outcomes.
Probability of an event = (Favourable outcomes/Total outcomes)

a) Fav. outcomes = 1
P(E) = 1/4

b) Fav. outcomes = 2
P(E) = 2/4 = 1/2

PS, your question made the point:

"Keep in mind, the coins are not tossed simultaneously."

The outcomes of two coins tossed simultaneously or a single coin tossed twice in succession would be the same.
The same would be true for 3 coins tossed simultaneously or a single coin tossed 3 times in succession,
4 coins ... , etc.

a) To find the probability of obtaining 2 heads when a coin is tossed twice, we can use the following steps:

Step 1: Determine the possible outcomes when a coin is tossed twice. There are four possible outcomes: HH, HT, TH, TT (where H represents a head and T represents a tail).

Step 2: Determine the favorable outcome(s) that meet the condition of obtaining 2 heads. In this case, there is only one favorable outcome: HH.

Step 3: Compute the probability by dividing the number of favorable outcomes by the total number of possible outcomes. The probability of obtaining 2 heads is therefore 1 favorable outcome divided by 4 possible outcomes, which simplifies to 1/4 or 0.25.

b) To find the probability of obtaining 1 head when a coin is tossed twice, we can use the following steps:

Step 1: Determine the possible outcomes when a coin is tossed twice. There are four possible outcomes: HH, HT, TH, TT (where H represents a head and T represents a tail).

Step 2: Determine the favorable outcome(s) that meet the condition of obtaining 1 head. In this case, there are two favorable outcomes: HT and TH.

Step 3: Compute the probability by dividing the number of favorable outcomes by the total number of possible outcomes. The probability of obtaining 1 head is therefore 2 favorable outcomes divided by 4 possible outcomes, which simplifies to 1/2 or 0.5.

To calculate the probability of obtaining a specific outcome, we need to divide the number of desired outcomes by the total number of possible outcomes.

In this case, we have a coin that is tossed twice. Each coin toss has two possible outcomes: heads (H) or tails (T). Therefore, there are 2^2 = 4 possible outcomes.

a) To find the probability of obtaining 2 heads, we need to determine how many of the 4 possible outcomes consist of getting heads twice. There is only 1 such outcome: HH (heads on both tosses). Therefore, the probability of obtaining 2 heads is 1/4.

b) To find the probability of obtaining 1 head, we need to determine how many of the 4 possible outcomes consist of getting heads once. There are 2 such outcomes: HT (heads on the first toss and tails on the second toss) and TH (tails on the first toss and heads on the second toss). Therefore, the probability of obtaining 1 head is 2/4, which simplifies to 1/2.