math (trigonometry)

help me solve this coz im stumped

secx-secx sin^2x= cosx

thanks

  1. 👍
  2. 👎
  3. 👁
  1. sec x (1 - sin^2x) = cos x
    sec x * cos^2 x = cos x
    (1/cos x)*(cos^2 x) = cos x
    cos x = cos x

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. trigonometry

    how do i simplify (secx - cosx) / sinx? i tried splitting the numerator up so that i had (secx / sinx) - (cosx / sinx) and then i changed sec x to 1/ cosx so that i had ((1/cosx)/ sinx) - (cos x / sinx) after that i get stuck

  2. precal- PLEASE HELP!

    secx/secx-tanx=sec^2x+ secx+tanx

  3. solving trig. equations

    tan(3x) + 1 = sec(3x) Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes secx and... secx = secx sec(3x) = sec(3x) [just put 3x back in for x- you don't really have to change 3x

  4. Pre-calculus

    Prove the following identities. 1. 1+cosx/1-cosx = secx + 1/secx -1 2. (tanx + cotx)^2=sec^2x csc^2x 3. cos(x+y) cos(x-y)= cos^2x - sin^2y

  1. Math

    secx+tanx/secx- tanx = 1+2sinx+sin^2x/ cos^2x

  2. Pre-Calc

    Use the fundamental identities and appropriate algebraic operations to simplify the expression. cosx / (1+sinx) Answer: secx Can someone please assist as to how I get to the answer?

  3. Trig

    If secx = 8 and -pi/2 < x < 0, find the exact value of sin2x Use the identity sin 2x = 2(sinx)(cosx) if secx = 8, then cosx = 1/8 where x is in the fourth quadrant. consider a right angled triangle with x=1, r=8, then y=?? by

  4. Math, please help

    Which of the following are trigonometric identities? (Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x 1-tanxtany=cos(x+y)/cosxcosy 4cosx sinx = 2cosx + 1 - 2sinx Find all solutions to the equation cosx

  1. Pre Calculus

    (cotx)(cscx)+secx=(csc^2x)(secx) Please help to verify this trigonometric identity.

  2. precal

    1/tanx-secx+ 1/tanx+secx=-2tanx so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx) =sinx/cosx+ sinx /cosx= -2tanxI but I know this can't be correct because what I did doesn't end as a

  3. Pre-Calculus

    Hi, I need a bit of help with verifying identities. The problems are as follows: sinx+cosx/cotx+1=sinx sin2x/sin - cos2x/cosx=secx 1-tan^2θ/1+tan^2θ=cos2θ

  4. precal

    cosx/secx+sinx/cscx=sec^2x-tan^2x

You can view more similar questions or ask a new question.