Room temperature is often assumed to be 25 Celsius. Calculate the molar volume of an ideal gas at 25 Celsius and 1 atm pressure.
Answer is 24.5L, Im trying to figure out how they got the answer. Help??
Use the ideal gas equation:
PV = nRT
n = number of moles = 1
P = Pressure = 1 atm
T = Temp. = 298K
R = 0.082 (when volume is in liter)
=> V = (nRT)/P
= (1*0.082*298)/1
= 24.5 L
Thank you so much!
How did u get 0.082
Oh constant
Well, 24.5 liters does sound like a jumbo-sized drink you'd get at a clown convention, but let me help you out here!
To find the molar volume of an ideal gas, we can use the ideal gas law equation: PV = nRT. Here, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the temperature from Celsius to Kelvin:
T(K) = T(C) + 273.15
So at 25 Celsius, the temperature in Kelvin would be 25 + 273.15 = 298.15 K.
Now, we can rearrange the ideal gas law equation to solve for V:
V = (nRT) / P
Since we're looking for the molar volume, we can assume that we have 1 mole of gas (n = 1), 1 atm pressure (P = 1 atm), and the ideal gas constant is R = 0.0821 L·atm/(mol·K).
Plugging in those values:
V = (1 mol * 0.0821 L·atm/(mol·K) * 298.15 K) / 1 atm
V = 24.46345 L
So, approximately 24.5 L is the molar volume of an ideal gas at 25 Celsius and 1 atm pressure.
Hope that clarifies things for you!
To calculate the molar volume of an ideal gas at a given temperature and pressure, you can use the ideal gas law, which states:
PV = nRT
Where:
P = Pressure
V = Volume
n = Number of moles of gas
R = Gas constant (0.0821 L•atm/(mol•K))
T = Temperature in Kelvin
First, let's convert the given temperature of 25 Celsius to Kelvin:
T(K) = T(C) + 273.15
T(K) = 25 + 273.15
T(K) = 298.15 K
Next, let's substitute the known values into the ideal gas law:
PV = nRT
(1 atm)(V) = (1 mol)(0.0821 L•atm/(mol•K))(298.15 K)
Now we can solve for V (volume):
V = (1 mol)(0.0821 L•atm/(mol•K))(298.15 K) / (1 atm)
Performing the calculation will give us the volume in liters:
V ≈ 24.5 L
Therefore, the molar volume of the ideal gas at 25 degrees Celsius and 1 atm pressure is approximately 24.5 liters.