Calculate the relative effusion rate of hydrogen and oxygen, given that both the gases are diatomic, with hydrogen having a molar mass of 2 grams and oxygen having a molar mass of 32 grams. Using Graham’s law equation.
rh/ro=sqrt(masso/massH0
= sqrt(32/2)=4
Graham's law of effusion states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. The equation for Graham's law is:
Relative rate of effusion of gas 1/Relative rate of effusion of gas 2 = √(molar mass of gas 2/molar mass of gas 1)
In this case, gas 1 is hydrogen with a molar mass of 2 grams and gas 2 is oxygen with a molar mass of 32 grams. Plugging these values into the equation, we get:
Relative rate of effusion of hydrogen/Relative rate of effusion of oxygen = √(32 grams/2 grams)
Simplifying this expression, we have:
Relative rate of effusion of hydrogen/Relative rate of effusion of oxygen = √16
Taking the square root of 16, we find that:
Relative rate of effusion of hydrogen/Relative rate of effusion of oxygen = 4
Therefore, the relative effusion rate of hydrogen to oxygen is 4:1.
To calculate the relative effusion rate of hydrogen and oxygen using Graham's law, we need to use the formula:
Relative Effusion Rate = sqrt(Molar Mass of Gas 1) / sqrt(Molar Mass of Gas 2)
Let's plug in the values given:
Molar Mass of Hydrogen (Gas 1) = 2 grams
Molar Mass of Oxygen (Gas 2) = 32 grams
Now, substitute these values into the formula:
Relative Effusion Rate = sqrt(2) / sqrt(32)
Simplifying further:
Relative Effusion Rate = sqrt(1/16)
= 1/4
= 0.25
Therefore, the relative effusion rate of hydrogen to oxygen is 0.25.