Algebra

Assume that S/A = 5.2, D/A = .40, N/E = .75 and A = D + E. Solve for N/S.

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asked by Jay
  1. A=D+E
    S/5.2=.4A + N/.75
    S/5.2=.4*S/5.2 + N/.75
    S(1/5.2-.4/5.2)=N/.75

    N/S= .75(1/5.2-.4/5.2)

    1. 0
    posted by bobpursley
  2. D = 0.40A
    A = D+E = 0.40A+E so E = 0.60A

    N = 0.75E = 0.45A
    S = 5.2A

    N/S = 0.45/5.2 = 45/520

    1. 0
    posted by Steve

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