A shock absorber is a form of spring that resists compression. If a 200.0 N force is applied to a particular shock absorber, it is compressed 2.1 cm. What is the proportionality constant for this shock absorber?
You have got to be kidding
F = k x
F = 200 N
x = 0.021 meter
To find the proportionality constant for the shock absorber, you can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:
F = k * x
Where:
F is the force applied to the shock absorber (200.0 N in this case)
k is the proportionality constant we want to find
x is the displacement or compression of the shock absorber (2.1 cm in this case)
Rearranging the equation, we have:
k = F / x
Substituting the given values, we get:
k = 200.0 N / 2.1 cm = 95.24 N/cm
Therefore, the proportionality constant for this shock absorber is 95.24 N/cm.