If the bearing of A from O is θ°T, then what is the bearing of O from A:
a. if 0° < θ° < 180°
b. if 180° < θ° < 360°?
I don't quite understand what the question is trying to ask, need some insight, thanks.
Draw a picture
say θ° is 30.
then from O to A is 180 + 30 = 210
for any θ° between 0 and 180, add 180
HOWEVER
once θ° is greater than 180, then when we add 180 it is bigger than 360
so to get it right you have to back up 180 and use θ° - 180
(or in fact you could still do it the same way and subtract 360 once you got 390 for example but that would be 180-360 = -180 anyway :)
or if A to O is east then O to A is west :} That might be where you got stuck.
riight, thanks. Appreciate it a lot Damon.
The question is asking about the bearing of point O from point A given the bearing of point A from point O. Bearing is a term used in navigation and describes the compass direction from one point to another. In this case, the bearing of A from O is θ°T which means that if you were standing at point O and looking towards point A, you would be facing θ°T on the compass.
To find the bearing of O from A, we use the following rule: the bearing of B from A is the bearing of A from B plus 180°. This rule holds true for any angle between 0° and 360°.
a. If 0° < θ° < 180°:
To find the bearing of O from A, we add 180° to θ°T. Therefore, the bearing of O from A would be (θ°T + 180°).
b. If 180° < θ° < 360°:
Similar to part a, we add 180° to θ°T to find the bearing of O from A. So, the bearing of O from A would be (θ°T + 180°).
In summary, for any angle value between 0° and 360°, the bearing of O from A can be found by adding 180° to the given bearing of A from O.