Margarito's class is running sprints. Each student has to run to a wall 100 yards away, slap it, then run back to the starting line. It takes Margarito 53 seconds to run from the starting line to the wall and back again. What was Margarito's average speed?

A.3.8 yd/s
B.1.9 yd/s
C.2.65 yd/s
D.0.38 yd/s

100/53 = _______ yd/s

thats what im here from

duh!

Do you mean that you cannot divide 100 by 53??

If the wall is 100 yards away that makes a distance of 200 yards she must run in that time.

I'm sorry. I goofed. Of course, DrBob222 is right.

To calculate Margarito's average speed, we need to divide the total distance covered by the total time taken.

First, let's find the total distance covered by Margarito. Since he runs from the starting line to the wall 100 yards away and then back to the starting line, the total distance covered is 2 times 100 yards, which is 200 yards.

Next, let's find the total time taken. According to the information provided, it takes Margarito 53 seconds to complete the round trip.

To calculate the average speed, we divide the total distance covered (200 yards) by the total time taken (53 seconds):

Average Speed = Total Distance / Total Time
Average Speed = 200 yards / 53 seconds.

Now, we calculate the average speed:

Average Speed ≈ 3.77 yd/s.

So, Margarito's average speed is approximately 3.77 yd/s.

Based on the given answer choices, the most accurate answer is A. 3.8 yd/s.