A rectangle has a perimeter of 24 units. The length of the rectangle is 2 times 3 less than the width. What is the width of the rectangle?
Perimeter = 2W + 2L
L = 2W - 3
24 = 2W + 2w - 3
Solve for W
To find the width of the rectangle, we need to set up an equation based on the given information.
Let's denote the width of the rectangle as 'w'.
According to the problem, the length of the rectangle is 2 times 3 less than the width. Therefore, the length can be represented as (2w - 3).
The perimeter of a rectangle is the sum of all its sides. In this case, the perimeter is given as 24 units.
The formula for the perimeter of a rectangle is: Perimeter = 2 * (Length + Width)
Plugging in the values we have:
24 = 2 * [(2w - 3) + w]
Now, we can solve the equation to find the value of 'w'.
Simplifying the equation:
24 = 2 * (3w - 3)
12 = 3w - 3
15 = 3w
w = 5
Therefore, the width of the rectangle is 5 units.