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How to use log tables?
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Given that log 2=0.3010 and log 3=0.4771, calculate without using mathematical tables or calculators, the values of
(A) log 54
Top answer:
(A) log 54 = log (2 x 3^3) = log 2 + 3 log 3 = 0.3010 + 3(0.4771) = 1.7323 (B) log 2.4 = log (24/10)
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Evaluation without using a calculator or mathematical tables :log 32+log 128-log 729/log 32+log 2-log 27
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To compute this expression without a calculator or mathematical tables, we can simplify and
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Calculate without using tables or calculators log 450 and log 324 given log 2 =0.3010 and log 3 =0.4771
Top answer:
log 450= log9 × log50 log3^2 × log 100÷2 Log100=2 So it's 2log3 × log 100÷2 2 (0.4771) × 2 -
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mathematically Evaluate without using tables 2 log base 10 raised 2 power 5 + log base 10 36 - log base10 9 that is, 2log10 5
Top answer:
The words are confusing, but it appears that you have 2log5 + log36 - log9 = log(25*36/9) = log100 =
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1)Without using mathematical tables or calculators,evaluate:2log5-3log2+5log2
2)log32+log128-log729÷log33+log2-log27
Top answer:
1) 2log5 - 3log2 + 5log2 = 2log5 - (3-5)log2 = 2log5 + 2log2 = 2(log5 + log2) = 2log(5 * 2) = 2log10
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Logarithm!!!
Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c)
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2 log 10 power 5 +log 10 power 8-1/2 log 10 power 4 answer
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Prove that log a, log ar, log ar^2 is an a.p.
Is the following below correct? Log ar^2 - Log ar= Log ar - Log a hence applying
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log a, log ar, log ar2, ...log a (r)^n now, log ar^n=log a + n log r consider the next term log
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write as a single logarithm:
-2logbase3(1/x)+(1/3)logbase3(square root of x) please show the steps to solving this. thanx.
Top answer:
To write the expression -2log₃(1/x) + (1/3)log₃(√x) as a single logarithm, we can apply the
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1)solve the equation log(6x-2)-1=log(x-3)
2)evaluate without using mathematical tables,the expression 2log 5-12log 16+2 log 40
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1) Starting with the equation log(6x-2)-1=log(x-3): We can use the property that
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solve for x: 3^2x+3=7^x+1
I did 2x+3=log0f3(7)+ logof3(7) (2-log of 3(7))x=log of 3(7)-3 x=log of 3 (7)+log of 3 (3^-3)/log 0f 3
Top answer:
I assume you meant 3^(2x+3) = 7^(x+1) Since the bases are in no way related, just take logs, in
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