The horse on a carousel is 3.6 m from the central axis. If the carousel rotates at 0.15 rev/s, how fast is a child on the horse moving in m/s?
what is r*angVelocity? change rev to radians /second.
Circumference = pi*2r = 3.14 * 7.2 m.
V = 0.15rev/s * 7.2m/rev =
To find the speed of a child on the horse, we need to consider the linear speed, which is the distance traveled per unit of time.
The linear speed of a point on a rotating object can be calculated using the formula:
Linear speed = 2πr × rotational speed
Where:
- r is the radius or distance from the central axis
- Rotational speed is the number of rotations per second
In this case, the horse is 3.6 m from the central axis, and the carousel rotates at 0.15 rev/s.
Let's calculate the linear speed:
Linear speed = 2π × 3.6 × 0.15
Linear speed = 2π × 0.54
Linear speed ≈ 3.38 m/s
Therefore, the child on the horse is moving at a speed of approximately 3.38 m/s.
To find the speed of the child on the horse, we need to calculate the tangential speed of the horse. Tangential speed is determined by the formula:
Tangential Speed = Angular Speed x Radius
First, let's calculate the radius of the horse from the central axis. Given that the horse is 3.6 m from the central axis, the radius will also be 3.6 m.
Now, we can substitute the values into the formula:
Tangential Speed = 0.15 rev/s x 3.6 m
To find the answer, multiply the angular speed by the radius:
Tangential Speed = 0.15 rev/s x 3.6 m = 0.54 m/s
Therefore, the child on the horse is moving at a speed of 0.54 m/s.