A chemist made 50 ounces of an acidic solution by mixing two different concentrations of the solution. He mixed x ounces of acidic solution with an 80% concentration and an acidic solution with 90% concentration. Which equation can be used to determine the concentration of the final solution?

What are your choices?

just add up the amounts of acid present. If there are x oz of 80% solution, then the rest (50-x) is 90%. That means that the final concentration c is found via

80x+90(50-x) = 50c
4500-10x = 50c

So, letting c(x) be the final concentration,

c(x) = 90-c/5

So, if x=0 (all 90% solution), c(0) = 90 and c(50) = 80 (all 80% solution).

oops: did you catch my typo?

To determine the concentration of the final solution, we need to set up an equation. Let's break down the problem:

The chemist made 50 ounces of the final solution by mixing two different concentrations. Let's assume he mixed x ounces of the acidic solution with an 80% concentration and (50 - x) ounces of the acidic solution with a 90% concentration.

So, the amount of acid in the x ounces of the 80% solution is 0.80 * x, and the amount of acid in the (50 - x) ounces of the 90% solution is 0.90 * (50 - x).

To find the concentration of the final solution, we need to calculate the total amount of acid in the 50 ounces of the mixed solution, and divide it by 50 ounces:

Total acid in the final solution = (0.80 * x) + (0.90 * (50 - x))

Final concentration of the solution = Total acid in the final solution / 50

Therefore, the equation that can be used to determine the concentration of the final solution is:

C = [(0.80 * x) + (0.90 * (50 - x))] / 50

where C represents the concentration of the final solution.