An object 2cm high is placed 20cm in the front of convex mirror of focal length of 10cm.So,that it is perpendicular to the principal axis.Find the poition and the size of the image.

To find the position and size of the image formed by a convex mirror, we can use the mirror equation:

1/f = 1/v - 1/u

where:
f = focal length of the mirror
v = image distance
u = object distance

Given:
f = 10 cm
u = -20 cm (negative sign indicates that the object is located in front of the mirror)

To find the image distance, we can rearrange the mirror equation to solve for v:

1/v = 1/f + 1/u
1/v = 1/10 + 1/-20
1/v = (2 - 1)/20
1/v = 1/20

v = 20 cm

So, the image distance is 20 cm. The negative sign indicates that the image is formed on the same side as the object (in front of the mirror).

To find the size of the image, we can use the magnification formula:

magnification (m) = -v/u

m = (-20)/(-20)
m = 1

The magnification is 1, which means that the image is the same size as the object.

Therefore, the position of the image is 20 cm in front of the convex mirror, and the size of the image is the same as the object.

To find the position and size of the image formed by a convex mirror, we can use the mirror formula and the magnification formula.

First, let's identify the given values:
- Object height (h0) = 2 cm
- Object distance (u) = -20 cm (negative sign indicates that the object is in front of the mirror)
- Focal length (f) = 10 cm

Now, let's use the mirror formula to find the image distance (v):
1/f = 1/u + 1/v

Substituting the given values:
1/10 = 1/-20 + 1/v

Simplifying the equation:
1/v = 1/10 + 1/20

1/v = (2 + 1)/20
1/v = 3/20

Taking the reciprocal of both sides:
v = 20/3 cm

The image distance (v) is positive, which indicates that the image is formed behind the mirror.

Next, let's use the magnification formula to find the size of the image (h1):
Magnification (m) = -v/u
m = -(20/3)/(-20)
m = 1/3

The magnification is positive, indicating that the image is upright.

Now, let's find the height of the image (h1):
h1 = m * h0
h1 = (1/3) * 2
h1 = 2/3 cm

Therefore, the position of the image is 20/3 cm behind the mirror, and the size of the image is 2/3 cm.

Give the answer of above question

sketch a ray diagram.

So the image is at the center of curvature, the image is real, inverted, same size, and is at the same location as the object.