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A body of 10kg and initially at rest is subjected to a force of 20N through a distance of 10m.calculate the change in kinetic energy of the body.

Workdone = KE

F*d =1/2mv^2
20*10 =1/2*10*v^2
200=10v^2/2
400/10=V^2
v=√40
K.E=1/2mv^2
KE=1/2*10*√40
KE=200J

Who said it was being lifted up?

work = force * distance = energy in

force = 20 N
distance = 10 m

work in = 20 N * 10 m = 200 Nm = 200 Joules = change in Ke if no change in height or energy sinks

Watts is Joules/second and unless you have typed this all wrong, power in watts has nothing to do with this.

great work

Nice job

PHYSICS

Work =force×distance

Force=20n
Distance=10m
Work=20n×10m=200nm
Or 200joules
Change in kinetic energy =potential energy
The final answer =200joules

500

To calculate the change in kinetic energy of the body, you need to use the formula:

ΔKE = 0.5 * m * (v_f^2 - v_i^2)

Where:
ΔKE = Change in kinetic energy
m = Mass of the body (10kg in this case)
v_f = Final velocity of the body
v_i = Initial velocity of the body

To find the final velocity, you can use Newton's second law of motion:

F = m * a

Where:
F = Force acting on the body (20N in this case)
m = Mass of the body (10kg)

Rearranging the equation, you can solve for acceleration (a):

a = F / m

Once you have the acceleration, you can use one of the kinematic equations to find the final velocity, given that the initial velocity is zero and the distance traveled is 10m:

v_f^2 = v_i^2 + 2 * a * d

Where:
d = Distance traveled (10m in this case)

Plugging in the values, we can calculate the final velocity (v_f), and then substitute it into the formula for the change in kinetic energy (ΔKE) to get the answer. Let's solve it step by step:

1. Calculate acceleration (a):
a = F / m = 20N / 10kg = 2 m/s^2

2. Calculate final velocity (v_f):
v_f^2 = v_i^2 + 2 * a * d
v_f^2 = 0 + 2 * 2 m/s^2 * 10m
v_f^2 = 40 m^2/s^2
v_f = √(40) ≈ 6.32 m/s

3. Calculate change in kinetic energy (ΔKE):
ΔKE = 0.5 * m * (v_f^2 - v_i^2)
ΔKE = 0.5 * 10kg * (6.32^2 - 0^2)
ΔKE = 0.5 * 10kg * (39.98 m^2/s^2)
ΔKE ≈ 199.9 J

Therefore, the change in kinetic energy of the body is approximately 199.9 Joules.

M=10kg

H=5M
G=10m/s^2
P.E=mgh
P.E=10m×5M×10m/s
^2=500Watts

M=10kg

H=5M
G=10m/s^2
P.E=mgh
P.E=10m×5M×10m/s
^2=500Watts
Since p.e=k.e
So it is 500Watts